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The online example says nothing about "pulling" You would only have to pull on it for the whole stroke if the buffer pressure were at or higher than P1. P2 is even lower. If the buffer pressure where lower than P2 no pulling would be necessary for the whole stroke, but a stop would be nee...

I own a "puny" portable sawmill that has a 1950's 13000 D8 Cat motor, diesel, that runs a 5' circular saw blade. It has a two cylinder gasoline/petral "pony" motor as the starting motor. It is both electric start and hand crank. The crank works better. Not sure why. Better spark ...

As you like to point out the "heat of compression" is "instantaneous" so it stops when the volume change stops.

The gas is being pushed through the regenerator to the hot space at the fastest rate. Compression is zero. Delta energy from compression is zero during this period.

I suppose I should mention the first is energy/work out, the second requires energy/work input. The first pushes, the second must be pulled. I hope this makes sense.

Given parameters: P1=P2 Atmospheric pressure plus constant weight on top, pressure stays constant for entire expansion. T2=2•T1 300 =T1 600 = T2 600 = 2•300 The example where P2=P1/2? Is for T1=T2 and V2=2•V1 Taking the same equation: P1•V1/T1= P2•V2/T2 Since T1=T2 they cancel each other, (multiple ...

Driving posters away opens the door for new posters to which your job, as educator, starts up at the beginning. As I've tried, you have identified an anomaly that bares further investigation. But it still may fit nicely into 200 year old and current theory. Your methods of discourse here suffer from...

P1V1/T1 = P2•V2/T2

For the given parameters:
P1=P2

Canceling P from both sides:
V1/T1 = V2/T2

From given parameters:
T2=2•T1

Inserting in to the equation:
P1/T1=P2/(2•T1)

Dividing both sides by (2•T1):
P1•(2•T1) / T1 = P2

Cancelling T1 top and bottom and rearranging:
2•P1 = P2

At TDC the piston is briefly not moving. Look at the piston's position verses time plot. It is at the top of the sine wave. It moves (rough numbers) 1% for a crank moving 5%. Compression is "over" before TDC, mostly over, especially in a LTD Stirling. At the same time the displacer is movi...

An isolated room, not to be confused with a closed room, is a room completely closed to everything. Nothing passes in or out. A closed room has a different definition. An isolated room can be at any temperature or pressure and contain any amount of internal energy, or enthalpy. However it won't have...

I had no idea I had done that. Oops. Me bad. Any other examples? P.S., I am the Fool and no one else. Matt is a good guy here out of good will and quite a bit over my head. I can barely keep up with him at times. Some of the others too. I also appreciate and learn from everyone here. Even you Tom, s...

Ahhhh.... Stroller beat me to it. LOL Regarding the copper verses steel block, I assume it is a weight difference. Just remember moving the displacer up and down is a temperature difference. Although both would move, I would think there would be a difference. I don't know how much. Pressure would be...

If the starting pressure at 300k and 100cc was 1atm + the added pressure of the 102g piston, it would be a basic pv=nrt calc. But if the temperature of 100cc at 300k and just 14.7psi is doubled to 600k, any additional weight will no longer allow expansion to 200cc. The only way to continue expansio...

The end of the compression stroke and beginning of the expansion stroke is where the displacer is moving away from the hot side pushing the gas to the hot side through the regenerator away from the cold side at the highest rate. The piston is at the top of its travel and is moving at its slowest rat...

Heat is not internal energy. To imply that the two are the same, as you often do, is misleading. To claim gases contract, as you do, is misleading. A Stirling engine has to concentrate heat by other means, certainly not by heat being "rejected to the cold plate". Especially considering at ...

Orifice=expansion valve=properly designed capillary tube=manually adjusted valve=needle valve All of which are missing. If you expect someone to believe that a short tiny length of not much smaller diameter tubing in a system with a tiny pump is equivalent to an orifice, please show us the numbers. ...