Stirlingengineforum.com

a2+b2=C2 would be pretty useless if it only worked for equilateral triangles. Pythagoras is spinning in his grave. :laugh: There is of course, no such thing as an equilateral right triangle. Which is the point. There is no such thing as a "perfect" Carnot engine either An algebraic formul...

You just type 5 paragraphs explaining that pistons leak How is a piston that stays cold, atmospheric temperature, going to heat up and seal? That's one reason I often make my own pistons if necessary, especially if running an engine on ice. Otherwise, as I've already said: "Most Stirling engin...

Yes. It's like being at a gas station. Adding a 1/4 tank of fuel. Driving for 400 miles. And saying wow, great milage on 1/4 tank 400%. Then putting 75% back in, to get to your starting point, and saying, "Ugh! I only got 25% percent." 100 out of 400. The difference for a heat engine is t...

You are mixing Stroller and my posts. No, Stroller & I apparently cross posted. I never even saw his post at all before posting. Yes the gas leaks by the piston in both directions. Nonsense. Now I can comment on Strollers post. Maybe if your piston and cylinder is so badly worn it can no longer...

Well, like I said before, you have some imagination.

Just reporting what you saw. Heated by a torch. Free piston getting closer to top/head, i.e., less gas cushion. Balloon not inflating because the same amount of gas is in the cylinder trapped by the balloon, but now on cold side of piston. What is there to imagine? You just wrote above: The piston ...

Sorry but using "all" of Qhz, all the "internal energy" down to absolute zero, all 100 joules added PLUS all the "given" 300 joules of "environmental heat" already inside the engine before heat was added, before the engine started, would be like 400% efficienc...

... If the cycle starts at Qcz, and DQh is added. It is then expanded doing work a maximum of Qhz Joules will be converted to work. The gas will be at T = 0 Kelvin and P=0. Now it must be compressed back to P=atmospheric an Tc=300 K. It will take 300 J to do so. That makes the machine's efficiency ...

Basically, plain and simply : n=(Qh-Qc)/Qh And : Q=Cv•M•T So : n = (Qh - Qc) / Qh n = (Cv•M•Th - Cv•M•Tc) / Cv•M•Th Simplifying : n = (Cv•M(Th-Tc) / Cv•M•Th Canceling : n = (Th-Tc) / Th If the cycle starts at Qcz, and DQh is added. It is then expanded doing work a maximum of Qhz Joules will be conv...

Begining of derivation: Taking the above 'noted' equation "Qhz = Qcz + DQh" and subtracting Qcz from both The term 'n' applies to the engine regardless of 'Qcz' base heat amount or reference point. I t will have the same efficiency burning the same energy at the same temperatures but with...

Begining of derivation: Taking the above 'noted' equation "Qhz = Qcz + DQh" and subtracting Qcz from both The term 'n' applies to the engine regardless of 'Qcz' base heat amount or reference point. It will have the same efficiency burning the same energy at the same temperatures but with ...

Tom, why would the balloon inflate? The gas heats up, expands, pushes the piston outward causing some inflation. The engine then runs. Any leakage by the piston would make the piston run closer to the closed end. The gas going by the piston would cool and return to it's original volume. Hence it wo...

But maybe gas can "stretch" like a rubber band. IDK. But I can see that the piston in a Stirling engine does infact return. Without a flywheel. Without a displacer. With no apparent "sink" or viable heat outlet. I've done the experiments myself, so I can't really just dismiss wh...

Begining of derivation: Taking the above 'noted' equation "Qhz = Qcz + DQh" and subtracting Qcz from both The term 'n' applies to the engine regardless of 'Qcz' base heat amount or reference point. It will have the same efficiency burning the same energy at the same temperatures but with ...

a2+b2=C2 would be pretty useless if it only worked for equilateral triangles. Pythagoras is spinning in his grave. :laugh: There is of course, no such thing as an equilateral right triangle. Which is the point. There is no such thing as a "perfect" Carnot engine either An algebraic formul...